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Ohm’s Law Calculator | Celtic Engineering Solutions
Celtic Engineering Toolbox

Ohm’s Law Calculator (V, I, R, P)

Fast, practical Ohm’s Law calculator used in real client projects at Celtic Engineering Solutions LLC. Enter any two of voltage, current, and resistance; we’ll compute the third and the power.

Ohm’s Law Calculator
Fill in any two values below and leave one box blank. The calculator will solve for the missing value and show power.
Quick presets
How to use this calculator
Think: “What do I want to find?” Leave that box empty, fill in the other two, and click Calculate.
  1. Decide what you are solving for:
    • Need the missing current? Leave I blank.
    • Need the missing resistance? Leave R blank.
    • Need the missing voltage? Leave V blank.
  2. Type numbers into the other two boxes. Use plain numbers only (no units in the field).
  3. Click Calculate.
  4. Read the results:
    • Voltage in volts (V)
    • Current in amps (A)
    • Resistance in ohms (Ω)
    • Power in watts (W)
Example 1 – LED from 5 V
You have a 5 V supply and a 220 Ω resistor. You want to know the current.
• V = 5, R = 220, leave I blank → click Calculate.
• Result: I ≈ 0.023 A (23 mA), P ≈ 0.11 W.
A ¼ W resistor is usually sufficient here.
Example 2 – Target current from 12 V
You want 50 mA from a 12 V supply.
• Convert 50 mA → 0.05 A.
• V = 12, I = 0.05, leave R blank → click Calculate.
• Result: R ≈ 240 Ω, P ≈ 0.6 W.
Choose at least a 1 W resistor for margin.
Core formulas and unit reminders

This calculator uses the basic Ohm’s Law and power relationships:

  • V = I × R   (voltage)
  • I = V ÷ R   (current)
  • R = V ÷ I   (resistance)
  • P = V × I   (power in watts)

Units used on this page:

  • Voltage in volts: V
  • Current in amps: A (0.02 A = 20 mA)
  • Resistance in ohms: Ω (1 kΩ = 1,000 Ω)
  • Power in watts: W
Scope. This tool is designed for low-voltage electronics (roughly 0–1000 V). For mains or high-voltage work, always follow relevant safety standards, clearance/creepage rules, and derating guidelines.
Quick design checks before you order parts

Use this checklist as a fast sanity check after you run the numbers.

  • Resistor power. Compare the calculated power (P) against the resistor’s rated power (¼ W, ½ W, 1 W, etc.). Use at least a 2× margin.
  • Source limits. Verify that the current is within the limits of the source (microcontroller pin, regulator, power supply).
  • Tolerance and variation. Real resistors have tolerance (±1%, ±5%). Consider both the highest and lowest possible current with those extremes.
  • Temperature. High power in a small package causes heating, drift, and reliability issues. When in doubt, move up in power rating and give the part room to breathe.
  • Safety-critical paths. For anything involving mains, high energy storage, or safety-related circuits, treat this tool as a starting point, not the final word.
Examples from Celtic Engineering Solutions

These are simplified versions of real situations where a quick Ohm’s Law check kept prototypes safe and predictable.

Example A
Limiting LED current on a 5 V microcontroller board
A status LED needed a forward current around 15–20 mA from a 5 V logic rail. The LED’s forward voltage was roughly 2 V.

Using V = I × R:
• V across the resistor ≈ 5 V − 2 V = 3 V
• Target current ≈ 0.015–0.02 A
• R ≈ 3 V ÷ 0.02 A = 150 Ω

The design used 220 Ω to be gentle on the LED and the MCU pin, with calculated power well under 0.25 W.
Example B
Choosing a sense resistor for a current-limited driver
A driver relied on a small sense resistor to limit current. The control IC expected about 0.5 V across the sense resistor at the target current of 100 mA.

• V across sense resistor = 0.5 V
• I = 0.1 A
• R = 0.5 V ÷ 0.1 A = 5 Ω
• Power = 0.5 V × 0.1 A = 0.05 W

A ¼ W 5 Ω resistor provided comfortable margin, and the driver behaved as expected on the bench.
Example C
Sanity-checking a box build at 24 V
A small enclosure used a 24 V supply feeding several resistive loads. A quick check confirmed currents and power were within connector and wiring limits.

For one branch:
• V = 24 V, R = 4.7 kΩ
• I ≈ 24 ÷ 4700 ≈ 5.1 mA
• P ≈ 24 × 0.0051 ≈ 0.12 W

Standard ¼ W resistors were sufficient, and heat rise inside the enclosure stayed modest.
Example D
Protecting an input from over-current
A board needed to accept a 12 V signal while feeding an isolated input stage that liked only a few milliamps.

Target current was set to 3 mA for robustness.
• V = 12 V, I = 0.003 A
• R = 12 ÷ 0.003 ≈ 4 kΩ
• Chosen value: 4.3 kΩ
• P ≈ 12 × 0.003 ≈ 0.036 W

Even a ⅛ W part would have worked; a ¼ W part was used for added headroom.
Not sure if your numbers are safe?
If your calculation involves mains voltage, motor loads, or anything safety-critical, treat this as a starting point. Send a short note with your values and constraints, and we’ll help you confirm a safe design direction.
Celtic Engineering Solutions LLC
Licensed Electrical Engineering • Prototyping • Product Design
Based in Murray, Utah
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